# ADD\_YEARS

### Description

`ADD_YEARS` takes a date, from either an information or in [ISO8601 format](https://docs.atfinity.io/rule-language/operators/date-operators), and a number of years to add, and returns a date with the given number of years added.

In the special case that the new year doesn't contain the original date (e.g. when adding a year to the leap day 29.02.2016) the new date will have the same number of days from the beginning of the year (e.g. 01.03.2017 in the earlier example).

### Example: Date

```
ADD_YEARS('2000-01-01', 18)
```

This returns `2018-01-01T00:00:00`, so the year 18 years after the 1st January 2000.

### Example: Date with time

If you specify not just a date, but a date and time in ISO8601 format, the function includes the time in the calculation.

```
ADD_YEARS('2000-01-01T09:35:23', 18)
```

This returns also the 1st January 2018, but at 9:35:23, so `2018-01-01T09:35:23`.